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Byju's Answer
Standard VII
Mathematics
Solving Equations with Variable on Both Sides
347 x-1-2 x-1...
Question
3
4
(
7
x
-
1
)
-
2
x
-
1
-
x
2
=
x
+
3
2
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Solution
We have:
3
4
(
7
x
−
1
)
−
2
x
−
1
−
x
2
=
x
+
3
2
⇒
3
4
(
7
x
−
1
)
−
2
x
+
1
−
x
2
−
x
=
3
2
⇒
3
×
7
4
x
−
3
4
−
2
x
+
1
2
−
x
2
−
x
=
3
2
⇒
21
4
x
−
2
x
−
x
2
−
x
=
3
2
+
3
4
−
1
2
(
By
transposition
)
⇒
21
x
−
8
x
−
2
×
x
−
4
x
4
=
1
+
3
4
⇒
21
x
−
14
x
4
=
7
4
⇒
7
x
4
=
7
4
⇒
x
=
1
CHECK: Substituting
x
=1 in the given equation, we get:
LHS=
3
4
(
7
x
−
1
)
−
2
x
−
1
−
x
2
=
3
4
(
7
×
1
−
1
)
−
2
×
1
−
1
−
1
2
=
3
4
×
6
−
2
=
9
2
−
2
=
9
−
4
2
=
5
2
RHS=
x
+
3
2
=
1
+
3
2
=
2
+
3
2
=
5
2
∴
LHS
=
RHS
Hence,
x
=1 is a solution of the given equation
.
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