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Stoichiometric Calculations

3A+2B→ A3 B2A...

Question

$3 A + 2 B \to A_{3} B_{2}$
$A_{3} B_{2} + 2 C \to A_{3} B_{2} C_{2}$
The above two reactions are carried out by taking 2 mol of each of B and C and 3 mol of A. Then which option(s) is/are correct?

1 mol of

A_{3} B_{2} C_{2}

is formed

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Half mol of

A_{3} B_{2} C_{2}

is formed

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Half mol of

A_{3} B_{2}

is formed in first reaction

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1 mol of

A_{3} B_{2}

is formed in first reaction

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Solution

The correct option is D 1 mol of $A_{3} B_{2}$ is formed in first reaction
$3 A + 2 B \to A_{3} B_{2} (balanced)$
$A_{3} B_{2} + 2 C \to A_{3} B_{2} C_{2} (balanced)$

Now, 3 mol of A reacts with 2 mol of B to form 1 mol of $A_{3} B_{2}$ .
So, 1 mol of $A_{3} B_{2}$ is formed when 3 mol of A and 2 mol of B are taken.
2 mol of C reacts with 1 mol of $A_{3} B_{2}$ to give 1 mol of $A_{3} B_{2} C_{2}$ .
Therefore, correct options are (a) and (d).

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Similar questions

3 A + 2 B \to A_{3} B_{2}

A_{3} B_{2} + 2 C \to A_{3} B_{2} C_{2}

The above two reactions are carried out by taking 2 mol of each of B and C and 3 mol of A. Then which option(s) is/are correct?

A + B \to A_{3} B_{2}

(unbalanced)

A_{3} B_{2} + C \to A_{3} B_{2} C_{2}

(unbalanced)
Above two reactions are carried out by taking 3 moles each of

A

and

B

and one mole of

C

. Then which option is/are correct?

A + B \to A_{3} B_{2}

A_{3} B_{2} + C \to A_{3} B_{2} C_{2}

The above two reactions are carried out by taking

4

moles each of

A

and

B

and

2

moles of

C

. Which of the following option(s) is/are correct?

A+B $⟶$ $A_{3} B_{2}$ (unbalanced) $A_{3} B_{2}$ +C $⟶$ $A_{3} B_{2} C_{2}$ (unbalanced)

Above two reactions are carried out by taking 3 moles each of A and B and one mole of C. Then which option is wrong

$A + B \to A_{3} B_{2}$ (unbalanced) $A_{3} B_{2} + C \to A_{3} B_{2} C_{2}$ (unbalanced) Above two reactions are carried out by taking 3 moles each of A and B and by taking one mole of C. Then which option(s) is/are correct?

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Stoichiometric Calculations

Standard XI Chemistry

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3A+2B→A3B2 A3B2+2C→A3B2C2 The above two reactions are carried out by taking 2 mol of each of B and C and 3 mol of A. Then which option(s) is/are correct?

$3 A + 2 B \to A_{3} B_{2}$
$A_{3} B_{2} + 2 C \to A_{3} B_{2} C_{2}$
The above two reactions are carried out by taking 2 mol of each of B and C and 3 mol of A. Then which option(s) is/are correct?