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3BaCl2 + 2Na3P04-->Ba3(PO4) 2 + 6NaCl.Maximum amount of Ba3(PO4)2 formed when2 moles each of Na3PO4 and BaCl2 are allowed to react is3'4(1) 4 mol (2) 1 mol (3)2/3 mol(4) 1/3mol

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