3m+2(m+2)=20-(2m-5)

In the second step- 3m+2m+4=20- 2m+5, how did 20-(2m-5) become 20-2m+5

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Solution

we actually do here is the multiplication of -ve sign in to the bracket

ie

20-(2m-5)

the step is as follows

separating the parts 20 and -(2m-5)

or -(2m-5) can be written as -1(2m-5)

= (-12m )- 5-1

-ve -ve is +ve (-5*-1= 5)

so answer become

20-2m+5

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3m+2(m+2)=20-(2m-5) In the second step- 3m+2m+4=20- 2m+5, how did 20-(2m-5) become 20-2m+5

we actually do here is the multiplication of -ve sign in to the bracket ie 20-(2m-5) the step is as follows separating the parts 20 and -(2m-5) or -(2m-5) can be written as -1*(2m-5) = (-1*2m )- 5*-1 -ve *-ve is +ve (-5*-1= 5) so answer become 20-2m+5

3m+2(m+2)=20-(2m-5)

In the second step- 3m+2m+4=20- 2m+5, how did 20-(2m-5) become 20-2m+5

we actually do here is the multiplication of -ve sign in to the bracket

ie

20-(2m-5)

the step is as follows

separating the parts 20 and -(2m-5)

or -(2m-5) can be written as -1(2m-5)

= (-12m )- 5-1

-ve -ve is +ve (-5*-1= 5)

so answer become

20-2m+5