4.0 g of a gas occupies 22.4 litres at NTP. The specific heat capacity of the gas at constant volume is 5.0 J/K-mol. If the speed of sound in this gas at NTP is 952 m/s, then the heat capacity at constant pressure is (Take gas constant R 8.3 JK mol) Here why we cannot use Cp-Cv=R

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Q. 4.0 g of a gas occupies 22.4 litres at NTP. The specific heat capacity of the gas at constant volume is 5.0

{J K}^{- 1} {m o l}^{- 1}

. If the speed of sound in this gas at NTP is 952

{m s}^{- 1}

, then the heat capacity at constant pressure is (Take gas constant R=8.3

{J K}^{- 1} {m o l}^{- 1}

)

4.0 g of a gas occupies 22.4L at NTP. The specific heat capacity of the gas at constant volume is 5.0 JK-1mol-1. If the speed of sound in the gas at NTP is 952 ms-1, then the heat capacity at constant pressure is.

(Take gas constant R=8.3 JK-1mol-1)

C_{v}

and

C_{p}

denote the molar specific heat capacities of a gas at constant volume and constant pressure, respectively. Then

Q. The molar specific heat capacity of an ideal gas, at constant pressure and at constant volume, are denoted by

C_{p} and C_{v}

, respectively. If

γ = \frac{C_{p}}{C_{v}} and R

is the universal gas constant, then

C_{v}

is equal to,

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