Question 19

40% of [100 - 20% of 300] is equal to
(a) 20
(b) 16
(c) 140
(d) 64

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Solution

40% of [100 - 20% of 300]
$= \frac{40}{100} \times [100 - \frac{20}{100} \times 300] = \frac{40}{100} [100 - 60] = \frac{40}{100} \times 40 = 4 \times 4 = 16$

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Question 19

40% of [100 - 20% of 300] is equal to
(a) 20
(b) 16
(c) 140
(d) 64

If $2 a = \sqrt{64}, t h e n \frac{a}{4}$ is equal to

Question 40

In $Δ A B C$ , $∠ A = 100^{\circ}$ , AD bisects $∠ A$ and $A D ⊥ B C$ . Then, $∠ B$ is equal to

a) $80^{\circ}$
b) $20^{\circ}$
c) $40^{\circ}$
d) $30^{\circ}$

Question 19

In the given figure, BC = CA and $∠ A = 40^{\circ}$ . Then, $∠ A C D$ is equal to

a) $40^{\circ}$
b) $80^{\circ}$
c) $120^{\circ}$
d) $60^{\circ}$

∠ A B C = 20^{\circ}

∠ A O C

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