The correct option is D 4300 ( 43) × ( 99) + 43 = [( 43) nbsp;× ( 99)] + 43 = [43× ( 1) nbsp;× ( 99)] + (43 × 1) (Since 43 × ( 1)= 43 and 43 = 43 × 1) ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Multiplication of Negative Numbers

-43 ×-99+43=

Question

$(- 43) \times (- 99) + 43 =$ ______

4300

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

-4300

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4257

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-4214

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
4300

$(- 43) \times (- 99) + 43$

$= [(- 43) \times (- 99)] + 43$

$= [43 \times (- 1) \times (- 99)] + (43 \times 1)$

$(S i n c e 43 \times (- 1) = - 43 a n d 43 = 43 \times 1$ )

$= (43 \times 99) + (43 \times 1)$

$= 43 (99 + 1)$

$[u s i n g d i s t r i b u t i v e p r o p e r t y, a \times (b + c) = (a \times b) + (a \times c)]$

$= 43 \times 100$

$= 4300$

Suggest Corrections

$99$	$93$	$39$	$43$	$93$
$39$	$66$	$43$	$33$	$44$

(−43)×(−99)+43= ______

The correct option is A 4300 (−43)×(−99)+43 =[(−43)×(−99)]+43 =[43×(−1)×(−99)]+(43×1) (Since 43×(−1)=−43 and 43=43×1) =(43×99)+(43×1) =43(99+1) [using distributive property,a×(b+c)=(a×b)+(a×c)] =43×100 =4300

$(- 43) \times (- 99) + 43 =$ ______