Question

$4abc+\frac{1}{3}abc+$ ___ $+$$\frac{2}{3}abc$ = 0

Answer 1

Let the term to be filled in the blank be $x$.

Then, $4abc+\frac{1}{3}abc+x+\frac{2}{3}abc=0$

$⟹$ $x=0-4abc-\frac{1}{3}abc-\frac{2}{3}abc$

$⟹$ $x=0-4abc-(\frac{1}{3}+\frac{2}{3})abc$

$⟹$ $x=-4abc-\left(1\right)abc$

$⟹$ $x=-5abc$