(4pq+3q)2 − (4pq−3q)2=
48pq2
Given, (4pq+3q)2−(4pq−3q)2
We know
(a+b)2=a2+2ab+b2
and (a−b)2=a2−2ab+b2
Applying these two identities, we can write tha above equation as
=[(4pq)2+(3q)2+2(4pq)(3q)]−[(4pq)2+(3q)2−2(4pq)(3q)]
=[(4pq)2−(4pq)2)+(3q2−3q2)+(24pq2+24pq2)
=24pq2+24pq2=48pq2