Question

$4y^2+12x-90y+67=0$

Answer 1

Consider the given equation,

$4y^2+12x-90y+67=0$ ……..(1)

Put $x=0,1,2,\mathrm{3.....}$

Put $x=0$ in equation (1),

$4y^2-90y+67=0$

$y=\frac{-(-90)\pm \sqrt{{(-90)}^2-4\times 4\times 67}}{2\times 4}$

$=\frac{90\pm \sqrt{8100-1072}}{8}$

$y=\frac{90\pm \sqrt{7028}}{8}=\frac{90\pm 83.83}{8}$

$y=100.479ory=0.771$

Hence,this is the answer.