Question

$4yz(z^2+6z-16)÷2y(z+8)$ gives

• A. z-2
• B. z(z-2)
• C. 2z(z-2)
• D. None of these

Answer 1

The correct option is C

2z(z-2)

$4yz(z^2+6z-16$)

Spiliting the middle term
= $4yz[z^2-2z+8z-16]$ (Since -2+8 = 6 and (-2) x (-8) = (-16))
= $4yz\left[z\right(z-2)+8(z-2\left)\right]$
= $4yz(z-2)(z+8)$
$\therefore$ $4yz(z^2+6z-16)÷2y(z+8)$
= $\frac{4yz(z-2)(z+8)}{2y(z+8)}$
= $2z(z-2)$