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5. A sample o...

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5. A sample of a hydrate of Barium Chloride weighing 61 gram was heated until all the water of hydration is removed. the dried sample weighed 52 gram. The formula of the hydrated salt is:

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Q. A sample of a hydrate of barium chloride weighing 61 g was heated until all the water of hydration is removed. The dried sample weighed 52 g. The formula of the hydrated salt is : (atomic mass, Ba = 137 amu, Cl = 35.5 amu)

250

g sample of a hydrated salt was heated at

110^{o} C

until all water was driven off. The remaining solid weighed

160

g. From these data, the percent of water by weight in the original sample can be correctly calculated as :

34.1 g

sample of a copper (II) chloride hydrate was heated to drive off the water. The remaining anhydrous sample was

26.9 g

. Find the number of waters hydration in the hydrate.

Q. A student was determining the formula for the hydrate of barium chloride,

B a {C l}_{2}

in a laboratory. The student cleaned, dried, and determined the mass of the crucible and cover and then added a sample of the hydrate to the crucible and determined the mas after that the sample was heated in crucible strongly for 10 minutes. The sample in the crucible and cover was cooled and the mass was determined. The mass data is provided in the table below:

Mass of crucible and cover	31.623 grams
Mass of crucible, cover, and sample prior to heating	33.632 grams
Mass of crucible, cover, and sample after heating	33.376 grams

After heating, determine how many moles of water were removed from the sample?

Q. A sample of hydrated salt is heated at

110^{o}

30

minutes until all the water is driven off. The recorded data is as follows:
Mass of the hydrate before heating

= 250

grams
Mass of the hydrate after heating

= 160

grams
From the above data, what is the percentage of water by mass in the original sample?

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