Question

Solve: $5\frac{1}{3}-[2\frac{1}{3}÷\{\frac{3}{4}-\frac{1}{2}\times (\frac{7}{10}-\frac{3}{5})\left\}\right]$

Answer 1

On solving according to BODMAS, we have

$5\left(\frac{1}{3}\right)-\left[2\right(\frac{1}{3})÷\{\left(\frac{3}{4}\right)-\left(\frac{1}{2}\right)\times (\frac{7}{10}-\frac{3}{5})\left\}\right]$

$=\left(\frac{16}{3}\right)-\left[\right(\frac{7}{3})÷\{\left(\frac{3}{4}\right)-\left(\frac{1}{2}\right)\times \left(\frac{35-30}{50}\right)\left\}\right]$

$=\left(\frac{16}{3}\right)-\left[\right(\frac{7}{3})÷\{\frac{3}{4}-\frac{1}{20}\left\}\right]$

$=\left(\frac{16}{3}\right)-\left[\right(\frac{7}{3})÷\left(\frac{15-1}{20}\right)]$

$=\left(\frac{16}{3}\right)-\left[\right(\frac{7}{3})÷(\frac{7}{10}\left)\right]$

$=\left(\frac{16}{3}\right)-\left[\right(\frac{7}{3})\times (\frac{10}{7}\left)\right]$

$=\left(\frac{16}{3}\right)-\left(\frac{10}{3}\right)$

$=\left(\frac{6}{3}\right)=2$