Ba(OH)2 is a di acidic base, i.e. 1 mol of Ba(OH)2 will give 2 moles of OH- ions,
there fore 0.01 M of Ba(OH)2 = 0.02 M OH- ions in 50 ml
50 ml Ba(OH)2 + 50 ml Water = 100 ml solution.
of OH- ions = 0.02 moles in 100 ml
pOH = -log [0.02] = 1.69
pH = 14-pOH
pH = 12.31