52 =
1 + 3 + 5 + 7 + 9 + 11
1 + 3 + 5 + 7
1 + 3 + 5
1 + 3 + 5 + 7 + 9
We know that the sum of first n odd numbers is n2.
Therefore,
52 = 1 + 3 + 5 + 7 + 9
The maximum and minimum values of f (x) = x50-x20 in the interval [0, 1] are