Expand:(5x+3)(x−1)(3x−2)
(5x+3)(x−1)(3x−2)=(5x+3)[x(3x−2)−1(3x−2)]=(5x+3)[3x2−2x−3x+2]=(5x+3)[3x2−5x+2]=5x(3x2−5x+2)+3(3x2−5x+2)=(5x×3x2−5x×5x+5x×2)+[3×3x2+3×(−5x)+3×2]=15x3−25x2+10x+9x2−15x+6=15x3−25x2+9x2+10x−15x+6=15x3−16x2−5x+6