Question

$[{(5z-2)}^2+40z]÷(5z+2)$

• A. 2z + 5
• B. 2z - 5
• C. 5z - 2
• D. 5z + 2

Answer 1

The correct option is D

5z + 2

Simplifying, we get:

$[{(5z-2)}^2+40z]=[25z^2-20z+4+40z]=[25z^2+20z+4]$

Factorizing:

$25z^2+20z+425z^2+20z+4={\left(5z\right)}^2+2\times \left(5z\right)\times 2+2^2{a}^2+2ab+b^2={(a+b)}^{2}25z^2+20z+4={(5z+2)}^2\left[\frac{({(5z-2)}^2+40z)}{(5z+2)}\right]=\frac{{(5z+2)}^2}{(5z+2)}=5z+2$