Find the value of $x : 6 (3 x + 2) - 5 (6 x - 1) = 3 (x - 8) - 5 (7 x - 6) + 9 x$

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Solution

We have: $6 (3 x + 2) - 5 (6 x - 1) = 3 (x - 8) - 5 (7 x - 6) + 9 x$
$\Rightarrow 18 x + 12 - 30 x + 5 = 3 x - 24 - 35 x + 30 + 9 x$
$\Rightarrow 18 x - 30 x - 3 x + 35 x - 9 x = - 24 + 30 - 12 - 5$
$\Rightarrow 53 x - 42 x = 30 - 41$
$\Rightarrow 11 x = - 11$
$\Rightarrow x = \frac{- 11}{11}$
$\Rightarrow x = - 1$
Therefore, value of $x$ is $- 1$ .

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