Question

60 ml of $H_2$ and 42 ml of $I_2$ are heated in a closed vessel. At equilibrium, the vessel contains $20mlHI$. What is the value of $k_C$?

• A. $K_C=0.125$
• B. $K_C=4.1$
• C. $K_C=0.019$
• D. $K_C=3.2$

Answer 1

Answer: (C)

$K_C=0.019$

$2HI\rightleftharpoons H_2+I_2$
$\frac{1638.4}{128}$ $\frac{7.8}{2}$
$\frac{203.2}{254}$ Moles at equilibrium
$12.8$ $3.9$ $0.8$
Let volume ofcontainer be $VL$
$\therefore K_C=\frac{\left[H_2\right]\left[I_2\right]}{{\left[HI\right]}^2}=\frac{3.9\times 0.8}{V\times V\times \frac{12.8}{V}}=0.019$
$\therefore K_C=0.019$