63.Solve the equation ; sin ax +cos bx =0

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\int e^{a x} sin b x d x = \frac{e^{a x}}{a^{2} + b^{2}} (a sin b x - b cos b x)

\int e^{a x} cos b x d x = \frac{e^{a x}}{a^{2} + b^{2}} (a cos b x + b sin b x)

s i n (a x) s i n (b x) = c o s (a x) c o s (b x) (a, b \neq 0

a \neq b)

\int \frac{s i n (a x) + c o s (b x)}{c o s (a x) + s i n (b x)} d x

α

α

a x^{2} + b x + c = 0

sin θ, cos θ

a x^{2} + b x + c = 0

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