65 + (10 \div 2 + 3 - 2 ) = ?
0
B Brackets
O Of
D Division
M Multiplication
A Addition
S Subtraction
According to BODMAS, here division will be done first.
10➗ 2 = 5
Hence, 65 + ( 5+3-2) = 65 + (8-2) = 65 +6 =71
Solve it using BODMAS.
65+(10÷2+3−2)=?
Solve the following using BODMAS:
65+(10÷2+3−2)
Find the value of:
(i) (−4)÷23
(ii) −35÷2
(iii) −45÷−3
(iv) −18÷34
(v) −213÷17
(vi) −712÷−213
(vii) 313÷−465