$6 x^{2} + 17 x + 5$ =?

(a) $(2 x + 1)$

(b) $(2 x + 5) (3 x + 1)$

(c) $(6 x + 5) (x + 1)$

(d) None of these

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Solution

(b) $(2 x + 5) (3 x + 1)$

$6 x^{2} + 17 x + 5 = 6 x^{2} + 15 x + 2 x + 5 = 3 x^{2} (x + 5) + 12 (x + 5) = (2 x + 5) (3 x + 1)$

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