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Question

8 four point charge of + 107C,107,C,2×107C and + 2×107 are placed respectively at the corner A, B,C, of a 0.05 m square. Find the magnitude of the resultant force on the charge at D.

A
0.2 dyne
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B
0.2 newton
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C
2 dyne
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D
0.02 newton
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Solution

The correct option is D 0.02 newton

8 four point charges of
Four charges are placed at corners of square at side length O, 0.5m and a charge is placed at centre (O) of square as shown in the fig.
Forces of repulsion on 1μC charges at O due to 2×107C charge at A and C are equal and opposite directions.
FC0=FA0=K(107×2×107)(0.052+0.052)2=0.02N
Therefore force are cancel to each other.

1238686_1192146_ans_419604980da2451a82abcaed07504409.png

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