8 \times (3 + 2 \times 2) = ?

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 56
B Brackets

O Of

D Division

M Multiplication

A Addition

S Subtraction

8 times (3 + 2 times 2) = $8 \times (3 + 2 \times 2)$

According to BODMAS, the operation inside the brackets has to be done first.

Hence, $(3 + 2 \times 2) = (3 + 4) = 7$ ,

then $8 \times 7 = 56$ .

Suggest Corrections

Similar questions

Q. Why this series occurs in square numbers.

0 \times 0 = 0, 1 \times 1 = 1 d i f f e r e n c e = 1 1 \times 1 = 1, 2 \times 2 = 4 d i f f e r e n c e = 3 2 \times 2 = 4, 3 \times 3 = 9 d i f f e r e n c e = 5 3 \times 3 = 9, 4 \times 4 = 16 d i f f e r e n c e = 7 4 \times 4 = 16, 5 \times 5 = 25 d i f f e r e n c e = 9 5 \times 5 = 25, 6 \times 6 = 36 d i f f e r e n c e = 11 6 \times 6 = 36, 7 \times 7 = 49 d i f f e r e n c e = 13 7 \times 7 = 49, 8 \times 8 = 64 d i f f e r e n c e = 15

7 \times 8 - 8 \times 4

$(- 2) \times (- 2) \times 2 \times - 2 = - 16$

Question 10

Which of the following is equal to 1?
$(a) 2^{0} + 3^{0} + 4^{0} (b) 2^{0} \times 3^{0} \times 4^{0} (c) (3^{0} - 2^{0}) \times 4^{0} (d) (3^{0} - 2^{0}) \times (3^{0} + 2^{0})$

If $a = 2^{3} \times 3^{4} \times 7^{2}$ and $b = 2^{3} \times 3^{2} \times 5^{3},$ then which of the following is true?

Join BYJU'S Learning Program

8 \times (3 + 2 \times 2) = ?

The correct option is C 56B Brackets O Of D Division M Multiplication A Addition S Subtraction 8 times (3 + 2 times 2) = 8×(3+2×2) According to BODMAS, the operation inside the brackets has to be done first. Hence, (3+2×2)=(3+4)=7, then 8×7=56.