Question

Solve: $8x+4=3(x-1)+7$

Answer 1

Given $8x+4=3(x-1)+7$
$\Rightarrow 8x+4=3x-3+7$
$\Rightarrow 8x-3x=-3+7-4$
$\Rightarrow 5x=0$
$\Rightarrow x=\frac{0}{5}$
$\therefore x=0$
To check:
Substitute $x=0$ in given equation, we get
$8x+4=3(x-1)+7$
$\Rightarrow (8\times 0)+4=3(0-1)+7$
$\Rightarrow 0+4=3\times (-1)+7$
$\Rightarrow 4=-3+7$
$\Rightarrow 4=4$
$\Rightarrow L.H.S=R.H.S$
Hence, it is correct.