8x+4 = 3 ( x 1) + 7 ⇒ 8x+4=3x 3+7 ⇒ 8x 3x= 3 +7 4 ⇒ 5x=0 ⇒ x=0/5=0 To check: 8x+4=3(x 1)+7 ⇒ 8 × 0+4=3(0 1)+7 ⇒ 0+4=3 × ( 1)+7 nbsp; nbsp; nbsp; ⇒ 4= 3+7 ...

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Standard VIII

Mathematics

Solving Equations with Variables on Both Sides

8x+4=3x-1+7

Question

Solve: $8 x + 4 = 3 (x - 1) + 7$

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Solution

Given $8 x + 4 = 3 (x - 1) + 7$
$\Rightarrow 8 x + 4 = 3 x - 3 + 7$
$\Rightarrow 8 x - 3 x = - 3 + 7 - 4$
$\Rightarrow 5 x = 0$
$\Rightarrow x = \frac{0}{5}$
$∴ x = 0$
To check:
Substitute $x = 0$ in given equation, we get
$8 x + 4 = 3 (x - 1) + 7$
$\Rightarrow (8 \times 0) + 4 = 3 (0 - 1) + 7$
$\Rightarrow 0 + 4 = 3 \times (- 1) + 7$
$\Rightarrow 4 = - 3 + 7$
$\Rightarrow 4 = 4$
$\Rightarrow L . H . S = R . H . S$
Hence, it is correct.

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Solving Equations with Variables on Both Sides

Standard VIII Mathematics

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Solve: 8x+4=3(x−1)+7

Given 8x+4=3(x−1)+7 ⇒8x+4=3x−3+7 ⇒8x−3x=−3+7−4 ⇒5x=0 ⇒x=05∴x=0 To check:Substitute x=0 in given equation, we get 8x+4=3(x−1)+7⇒(8×0)+4=3(0−1)+7 ⇒0+4=3×(−1)+7⇒4=−3+7 ⇒4=4 ⇒L.H.S=R.H.S Hence, it is correct.

Solve: $8 x + 4 = 3 (x - 1) + 7$