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Byju's Answer
Standard XII
Mathematics
Standard Formulae - 1
90.General so...
Question
90.General solution of 3tan(-15)=tan(+15)
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Q.
The solution of
3
tan
(
A
−
15
∘
)
=
tan
(
A
+
15
∘
)
is
Q.
If
3
tan
(
θ
−
15
o
)
=
tan
(
θ
+
15
o
)
,
0
<
θ
<
90
o
, then
θ
=
45
o
Q.
The solution of the inequality
(
tan
−
1
x
)
2
−
3
tan
−
1
x
+
2
≥
0
is -
Q.
The solution of the inequality
(
tan
−
1
x
)
2
−
3
tan
−
1
x
+
2
≥
0
is-
Q.
If
3
tan
(
θ
−
15
o
)
=
tan
(
θ
+
15
o
)
,
0
o
<
θ
<
90
o
, then
sin
θ
+
cos
θ
is equal to _________.
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