Question

$9se{c}^2\theta$ - $9ta{n}^2\theta$ is equal to:

• A. 1
• B. -1
• C. 9
• D. -9

Answer 1

The correct option is C

9

We know that , $se{c}^2\theta$ - $ta{n}^2\theta$ = 1
Therefore, $9se{c}^2\theta$ - $9ta{n}^2\theta$ = 9($se{c}^2\theta$ - $ta{n}^2\theta$) = 9