Sinusoidal AC
Trending Questions
Q. The voltage of an ac supply varies with time (t) as V=120 sin 100 π t cos 100 π t. The maximum voltage and frequency respectively are
- 120 volts, 100 Hz
- 120√2 volts, 100 Hz
- 60 volts, 200 Hz
- 60 volts, 100 Hz
Q. The equation of an alternating voltage is V =100 sin 100 π t volt. Its peak value and frequency are
- 100 V, 50 Hz
- 50V, 100Hz
- 200 V, 100 Hz
- 100 V, 200 Hz
Q. Match the following
Currentsr.m.s values(1) x0 sin ω t(i) x0(2) x0 sin ω t cos ω t(ii) x0√2(3) x0 sin ω t+x0 cos ω t(iii) x0(2√2)
Currentsr.m.s values(1) x0 sin ω t(i) x0(2) x0 sin ω t cos ω t(ii) x0√2(3) x0 sin ω t+x0 cos ω t(iii) x0(2√2)
- 1. (i), 2. (ii), 3. (iii)
- 1. (ii), 2. (iii), 3. (i)
- 1. (i), 2. (iii), 3. (ii)
- None of these
Q. The voltage of an ac supply varies with time (t) as V=120 sin 100 π t cos 100 π t. The maximum voltage and frequency respectively are
- 120 volts, 100 Hz
- 120√2 volts, 100 Hz
- 60 volts, 200 Hz
- 60 volts, 100 Hz
Q. The voltage of an ac source varies with time according to the equation V=100 sin 100 π t cos 100 π t where t is in seconds and V is in volts. Then
- The peak voltage of the source is 100 volts
- The peak voltage of the source is 50 volts
- The peak voltage of the source is 100√2 volts
- The frequency of the source is 50 Hz
Q. An ac voltage is represented by E=220√2 cos(50π)t. The current becomes zero times in 1 sec.
- 25
- 50
- 75
- 100
Q. The voltage of an ac source varies with time according to the equation V = 200sin(100π t).cos(100π t) where t is in seconds and V is in volts. Then
- The peak voltage of the source is 100 volts
- The peak voltage of the source is 50 volts
- The peak voltage of the source is 100√2 volts
- The frequency of the source is 50 Hz
Q.
An ac voltage is represented by E=220√2 cos(50π)t How many times will the current becomes zero in 1 s?
50 times
100 times
30 times
25 times
Q. The peak value of an alternating emf is given by E=E0cos(wt) is 10 volt and its frequency is 50 Hz. At a time t=(1600) second, the instantaneous value of the emf is:
- 1V
- 5V
- 5√3V
- 10V
Q. The equation of an alternating voltage is V =100 sin 100 π t volt. Its peak value and frequency are
- 100 V, 50 Hz
- 50V, 100Hz
- 200 V, 100 Hz
- 100 V, 200 Hz