Ionisation Energy
Trending Questions
IE1=250 kJ mol−1
IE2=820 kJ mol−1
IE3=1100 kJ mol−1
IE4=1400 kJ mol−1
Find out the number of valence electrons from the element X.
- 3
- 4
- 2
- 1
- CsI
- CsF
- NaF
- LiF
(i) The size of a Cl− ion is greater than the size of a Cl atom.
λ∞m for Ba(OH)2=457.6 ohm−1cm2mol−1.
λ∞m for Ba(Cl2)=240.6 ohm−1cm2mol−1.
λ∞m for NH4Cl=128.8 ohm−1cm2mol−1.
- −238.3 ohm−1cm2mol−1
- 212.6 ohm−1cm2mol−1
- 338.4 ohm−1cm2mol−1
- 238.3 ohm−1cm2mol−1
Among lanthanoid lala3+ & lu3+ ions are
A)paramagnetic B)Diamagnetic C) ferromagnetic
D)All of these
Please with explaination
- Na+
- Mg2+
- F−
- O2−
Among the statements (I–IV), the correct ones are:
(I) has a smaller atomic radius compared to .
(II) has higher ionization enthalpy than .
(III) Charge/radius ratio of is greater than that of .
(IV) Both and form mainly covalent compounds.
(I), (II) and (IV)
(I), (II) and (III)
(II), (III) and (IV)
(I), (III) and (IV)
Arrange F, Cl, O, N in the decreasing order of electronegativity
Cl > F > N > O
F > O > N > Cl
F > N > Cl > O
O > F > N > Cl
- None of the above
Successive ionization enthalpies of an element 'X' are given below
IE1. IE2. IE3. IE4
165. 195. 556. 595
Electronic configuration of the element'X' is?
- 1s22s22p63s2
- 1s22s22p63s1
- 1s22s22p6
- 1s22s22p5
- Cl
- Cs
- I
- Li
Why are 13th group elements able to form covalent bond?
What is ionization enthalpy?
it is said that in the valence shell of lithium one proton is pulling one electron and in berilium two protons are pulling two electrons. but the atomic radius of lithium is bigger than berilium.if the amount of attraction according to their valency will be equal. then why?
[1 Mark]
- H2Po<H2Te<H2Se<H2S<H2O
- H2Po<H2O<H2Te<H2Se<H2S
- H2S<H2O<H2Te<H2Se<H2Po
- H2O<H2S<H2Te<H2Se<H2Po
The first ionisation enthalpies (kj/mol)for Li , Be , B and C have one of the following values. Which of these corresponds to that of boron ?
520
1086
899
800
- P3Q2R4X
- P2Q2R3X2
- P3QR4X
- P4QR4X2
- a > b > c > d
- d > b > c > a
- b > d > a > c
- b > a > d > c
- 5.96×10−2
- 5.96×10−1
- 5.96×10−3
- 5.96