Vn Method
Trending Questions
Q.
If , then
greater than or equal to
Q. The sum of the following series
1+6+9(12+22+32)7+12(12+22+32+42)9 +15(12+22+...+52)11+...up to 15 terms, is :
1+6+9(12+22+32)7+12(12+22+32+42)9 +15(12+22+...+52)11+...up to 15 terms, is :
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Q.
The sum of the series is equal to:
Q. Sum of n terms of the series √2+√8+√18+√32+........ is
Q. If S=∞∑n=23n2+1(n2−1)3 then 16S is
Q.
Find of .
Q.
The value of is
Q. If a+b+c+d=63, where a, b, c, d∈I+, then the maximum value of ab+bc+cd is
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Q. If √5+x+√5−x√5+x−√5−x=4, then value of x is
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Q.
If the sum of the series is a finite number, then:
None of these
Q. Let S=16+124+160+1120+⋯ upto ∞. Then the value of 2S is
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- 2
Q.
limn→∞[11.3+13.5+15.7⋯1(2n+1)(2n+3)] is equa to
19
12
0
2
Q. The sum to infinity of the series
13+33⋅7+53⋅7⋅11+73⋅7⋅11⋅15+⋯ is
13+33⋅7+53⋅7⋅11+73⋅7⋅11⋅15+⋯ is
Q.
Statement I. The sum of the series is .
Statement II , for any natural number
Statement I is false, Statement II is true
Statement I is true, Statement II is true; Statement II is a correct explanation of Statement I
Statement I is true, Statement II is true; Statement II is not a correct explanation of Statement I
Statement I is true, Statement II is false
Q. Let rth term of a series be given by Tr=r1−3r2+r4. Then −2∞∑r=1Tr is
Q. The sum to 50 terms of the series 312+512+22+712+22+32+… is
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Q. The nth term of a sequence of numbers is an and given by the formula an=an−1+2n for n≥2 and a1=1.
The sum of first 20 terms is
The sum of first 20 terms is
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Q. If ak=1k(k+1), for k=1, 2, 3.....n, then (n∑k=1ak)2=
Q. Show that f(x)=2x+cot−1x+log(√1+x2−x) is increasing in R.
Q. 99∑r=1r!(r2+r+1)=
- 102!−100!
- 100(100!)−1
- 99(100!)−1
- 100(99!)−1
Q. If Sr denotes the sum of the infinite geometric series whose first term is r and common ratio is 11+r, where r∈N, then the value of 10∑r=1S2r is
- 385
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- 384
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Q. The sum of 10 terms of the series 2⋅5+5⋅8+8⋅11+… is
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Q. The sum of 10 terms of the series 1.3.5+3.5.7+5.7.9+…… is
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- 28680
Q.
If are acute angles such that . Then is
None of these
Q. The sum of first 10 terms of the series 1⋅2⋅3+2⋅3⋅4+3⋅4⋅5+......... is
- 6006
- 2970
- 3990
- 4290