2nd Equation of Motion
Trending Questions
A bus starting from rest moves with a uniform acceleration of for . Find
- the speed acquired,
- the distance traveled.
A trolley, while going down an inclined plane, has an acceleration of . What will be its velocity after the start?
Two trains A and B of length 400 m each are moving on two parallel tracks with a uniform speed of 72 kmh−1 in the same direction, with A ahead of B. The driver of B decides to overtake A and accelerates by 1 m/s2. If after 50 s, the guard of B just brushes past the driver of A, what was the original distance between them?
Show that path of projectile is parabola?
A particle travels 10m in first 5sec and 10m in next 3sec . Assuming constant acceleration what is the distance travelled in next 2sec.
- 10.3 m
- 9.3 m
- None of above
- 8.3 m
A particle experiences constant acceleration for 20 seconds after starting from rest. If it travels a distance s1 in the first 10 seconds and distance s2 in the next 10 seconds, then
- s2=s1
- s2=2s1
- s2=3s1
- s2=4s1
A particle moving with a uniform acceleration travels and in the first two consecutive intervals of each. Its initial velocity will be.
- 800 m
- 750 m
- 700 m
- 850 m
In the third second, the distance traveled by a particle starting from rest and traveling with an acceleration of is
- 10×104 m/s2
- 12×104 m/s2
- 13.5×104 m/s2
- 15×104 m/s2
The motion of a particle along a straight line is described by equation x=8+12t -t3 , , where x is in metre and t is in second. What is the retardation of the particle when its velocity becomes zero
A ball is thrown vertically upwards attains a maximum height of 45m. What is the time after which velocity of the ball become equal to half the velocity of projection?
- 5 m
- 1 m
- 6 m
- 4 m
- 1:2:4
- 1:2:5
- 1:3:5
- 1:3:9
Let m1=1kg m2=2kg and m3=3 kg in figure.
Find the accelerations of m1, m2, and m3. The string from the upper pulley to m1 is 20 cm when the system is released from rest. How long will it take before m1 strikes the pulley ?
- 30 sec
- 15 sec
- 10 sec
- 5 sec
- 10 cm/s
- 20 cm/s
- 5 cm/s
- 30 cm/s
- 8 m/s
- 6 m/s
- 4 m/s
- 12 m/s
- 2.5 m/s
- 5.5 m/s
- 11 m/s
- 4 m/s
- 2.5s
- 3.5s
- 1.5s
- 4.5s
- The kinetic energy after a displacement y is qEy
- The horizontal and vertical components of acceleration are ax=0, ay=qEm
- The equation of trajectory is y=12(qE2xmv2)
- The horizontal and vertical displacements x and y after a time t are x=vt and y=12ayt2
- 9/25
- 3/5
- 25/9
- 1/25