Acceleration in 1D
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Q. The figure shows the v - t graph of a particle moving in straight line. Find the time (in s) when particle returns to the starting point.
Q. A particle moves along x-axis as x=4(t-2)+a(t−2)2 Which of the following is true?
- The initial velocity of particle is 4
- The particle is at origin at t = 0
- None of these
- The acceleration of particle is 2a
Q. At zero acceleration, a particle moves along a straight line. What is the velocity of a particle at the position of x = t4−20t2+42?
- -48.68 m/sec
- +48.68 m/sec
- -42 m/sec
- + 42 m/sec
Q. Starting from the origin at time t=0, with initial velocity 5^j ms−1, the particle moves in the x−y plane with a constant acceleration of (10^i+4^j) m/s2. At time t, its coordinates are (20 m, y0 m). The values of t and y0 are, respectively:
- 2 s and 18 m
- 4 s and 52 m
- 2 s and 24 m
- 5 s and 25 m
Q. The acceleration of a particle is defined by the relation, a=−4x(−1+14x2) , where x is displacement along x− axis. All the quantities are in SI units. If velocity of the particle (v)=17 m/s when x=0, then the velocity of the particle when x=4 m is
- 12 m/s
- 15 m/s
- 20 m/s
- 25 m/s
Q. The velocity of a particle at t=0 at origin is →u=4^i+3^j m/sec and a constant acceleration is →a=6^i+4^j m/sec2. Find the displacement of the particle at t=2 sec
- (20^i+14^j) m
- (20^i−14^j) m
- (−20^i+14^j) m
- (−20^i−14^j) m
Q. Starting from the origin at time t=0, with initial velocity 5^j ms−1, a particle moves in the xy− plane with a constant acceleration of 10^i+4^j ms−2. At time t, its coordinates are 20 m, y0 m. The values of t and y0 are, respectively-
- 2 s and 18 m
- 4s and 52 m
- 2 s and 24 m
- 5 s and 25 m
Q. A particle moves from the point (2.0 ^i+4.0 ^j) m, at t=0, with an initial velocity (5.0 ^i+4.0 ^j) ms−1. It is acted upon by a constant force, which produces a constant acceleration of (4.0 ^i+4.0 ^j) ms−2. What is the distance of the particle, from the origin, at time 2s?
- 5 m
- 10√2 m
- 20√2 m
- 15 m
Q. A particle is moving along straight line (x axis) & position of particle is given by x=t2−7t+12, then at t=3.2, the speed of particle will
- increase
- decrease
- become zero
- increase or decrease
Q. The acceleration of a particle is defined by the relation, a=−4x(−1+14x2) , where x is displacement along x− axis. All the quantities are in SI units. If velocity of the particle (v)=17 m/s when x=0, then the velocity of the particle when x=4 m is
- 12 m/s
- 15 m/s
- 20 m/s
- 25 m/s
Q. The figure shows the v - t graph of a particle moving in straight line. Find the time (in s) when particle returns to the starting point.
Q. The figure shows the v - t graph of a particle moving in straight line. Find the time (in s) when particle returns to the starting point.
Q. The figure shows the v - t graph of a particle moving in straight line. Find the time (in s) when particle returns to the starting point.
Q. The figure shows the v - t graph of a particle moving in straight line. Find the time (in s) when particle returns to the starting point.
Q. The displacement of a body along y-axis is given by, 2y=gt2 (g is a constant & t is the time taken). What will be the acceleration of the body along y-axis at any time t ?
- g
- 12gt
- None of these
- 2g
Q. The acceleration of a particle is defined by the relation, a=−4x(−1+14x2) , where x is displacement along x− axis. All the quantities are in SI units. If velocity of the particle (v)=17 m/s when x=0, then the velocity of the particle when x=4 m is
- 12 m/s
- 15 m/s
- 20 m/s
- 25 m/s
Q. The acceleration of a particle is defined by the relation, a=−4x(−1+14x2) , where x is displacement along x− axis. All the quantities are in SI units. If velocity of the particle (v)=17 m/s when x=0, then the velocity of the particle when x=4 m is
- 12 m/s
- 15 m/s
- 20 m/s
- 25 m/s