Displacement
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A drunkard walking in a narrow lane takes 5 steps forward and 3 steps backward, followed again by 5 steps forward and 3 steps backward, and so on. Each step is 1 m long and requires 1 s. Plot the x-t graph of his motion. Determine graphically and otherwise how long the drunkard takes to fall in a pit 13 m away from the start.
- 25 m
- 25.5 m
- 30 m
- 22.4 m
A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1 m long and takes 1 s. There is a pit on the road 11 m away from the starting point. The drunkard will fall into the pit after:
- 37 s
- 21 s
- 29 s
- 31 s
The position of a body moving along x-axis at t is given by x=(t2-4t+6)m. The distance travelled by body in time interval t=0 to t=3 s is
(A) 5m
(B) 7m
(C) 4m
(D) 3m
- 13
- 11
- 9
- 7
- 1.5 km
- 2 km
- 2.5 km
- 3 km
- 2 π R
- π R
- R√π2+1
- R√π2+4
- √50 km and tan−1(5)
- √10 km and tan−1(√5)
- √52 km and tan−1(5)
- √52 km and tan−1(√5)
- 5√3 m
- 10√3 m
- 20√3 m
- 30√3 m
a. 40m, 0
b. 40m, 20m
c. 40m, -20m
d. 60m, -20m
- 26 seconds
- 31 seconds
- 37 seconds
- 41 seconds
- 16 m
- 64 m
- 48 m
- 32 m
A body is released from the top of a tower of height H m. After 2 s, it is stopped and then instaneously released. What will be its height after next 2 s ?
(H-5) m
(H-10) m
(H-20) m
(H-40) m
A body starts from rest with uniform acceleration. The velocity of the body after t seconds is v. The displacement of the body in last three seconds is
The displacement x of a particle at the instant when its velocity is v is given by v=√3x+16. Its acceleration and initial velocity are
1.5 unit, 4 unit
3 unit, 4 unit
16 unit, 1.6 unit
16 unit, 3 unit
A boy starts from his house and travels to reach his school. On finding it closed, he returns to his house. What is,
(a) the distance travelled by the boy (b) the final displacement of the boy.
A particle moves along a circular path from one point to a diametrically opposite point, what is the magnitude of its displacement?
- 11.2 m
- 13.8 m
- 14.3 m
- 15.4 m
- Zero
- 2 m
- 3 m
- 4 m
- 13 m
- 15 m
- 12 m
- 5 m
i. Distance can be negative.
ii. Displacement can't be greater than Distance.
iii. Displacement is always less than Distance.
iv. Displacement can be equal to Distance.
- ii & iii
- ii & iv
- i & iii
- ii, iii & iv
- 22.4 m
- 25 m
- 25.5 m
- 30 m
- 10 m along north
- 10 m long south
- 10 m along west
- Zero
- 10 m along north
- 10 m long south
- 10 m along west
- Zero
For the motion on a straight-line path with a constant acceleration, the ratio of the magnitude of the displacement to the distance covered is
What is difference between path length and distance?(not displacement)