Final Velocities
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What are deforming force and restoring force?
- Total momentum of the system is 7 kg ms−1.
- Momentum of 5 kg mass after collision is 5 kg ms−1.
- Velocity of 5 kg after collision is 1 m/s.
- Velocity of 1 kg before collision is 2 m/s.
X=6cos(100t+π/4)cm
Determine the maximum kinetic energy of the body.
Two blocks of masses 10 kg and 20 kg moving at speeds of 10 m s−1 and 20 m s−1 respectively in opposite directions, approach each other and collide. If the collision is completely inelastic, find the thermal energy developed in the process.
A disc of mass 5kg and radius 50cm rolls on the ground with a velocity of 10m/s . Calculate the kinetic energy of disc ( I= MR2/2)
A bomb at rest explodes into two fragments of mass 3 kg and 1 kg The total kinetic energy of fragments is 6×104 J. Calculate kinetic energy of bigger fragment.
![](https://search-static.byjusweb.com/question-images/byjus/ckeditor_assets/pictures/891774/original_Coll_Q10.png)
- 0.6v to the left
- 0.4v to the left
- zero
- 0.4v to the right
- 0.9 kg
- 1.8 kg
- 1.2 kg
- 1.5 kg
![](https://search-static.byjusweb.com/question-images/byjus/ckeditor_assets/pictures/891682/original_Coll_Q11.png)
- 9 m/s, 3 m/s
- 7 m/s, 3 m/s
- 9 m/s, 2 m/s
- 7 m/s, 2 m/s
![](https://search-static.byjusweb.com/question-images/byjus/ckeditor_assets/pictures/960666/original_36.png)
- (34)n−1√5gr
- (43)n−1√5gr
- (32)n−1√5gr
- (23)n−1√5gr
![](https://search-static.byjusweb.com/question-images/byjus/ckeditor_assets/pictures/892565/original_Q18.png)
- v99
- v100
- v
- zero
Consider a gravity-free hall in which an experimenter of mass 50 kg is resting on a 5 kg pillow, 8 ft above the floor of the hall. He pushes the pillow down so that it starts falling at a speed of 8 ft/s. The pillow makes a perfectly elastic collision with the floor, rebounds and reaches the experimenter's head. Find the time elapsed in the process.
2.88 s
1.22 s
2.22 s
0.22 s
- 10 J
- 20 J
- 40 J
- 30 J
A body of mass 1 kg makes an elastic collision with another body at rest and continues to move in the original direction after collision with a velocity equal to 14 of its original velocity. The mass of the second body is
- \N
- 5
- 10
- 15
- 20
Name the force involved in the following cases:
A stretched rubber band regains its original shape.
![](https://search-static.byjusweb.com/question-images/byjus/ckeditor_assets/pictures/912199/original_10_S.png)
- The velocity of the mass 2m after collision will be 2u3
- The velocity of the mass m after collision will be 2u3
- Time elapsed for next collision after their first collision will be 2πru
- All the above.
- 4:9
- 2:3
- 3:2
- 9:4
- 0.8 m/s
- 0.5 m/s
- 0.3 m/s
- 1.2 m/s
- m2m1=9+2√2
- m2m1=3−2√2
- m1m2=3−2√2
- m1m2=9+√2
- 5 m/s
- 10 m/s
- 25 m/s
- 20 m/s
![](https://search-static.byjusweb.com/question-images/byjus/ckeditor_assets/pictures/892511/original_Q16.png)
- VA=4 m/s VB=6 m/s
- VA=3 m/s VB=2 m/s
- VA=2 m/s VB=3 m/s
- VA=6 m/s VB=4 m/s
![](https://search-static.byjusweb.com/question-images/byjus/ckeditor_assets/pictures/877005/original_Picture27.png)
- m1>m2
- m1<m2
- m1=m2
- There is no relation between m1 and m2
- 100 m/s
- 0 m/s
- 10 m/s
- 5 m/s
1. Gusset plate material is saved by using a lug angle but extra material is required for lug angles and their connection.
2. The load carrying capacity of the tension member will be maximum if gusset plate is in between the two angles and tacking rivets are provided.
- 1 only
- 2 only
- 1 and 2 both
- None of these
A sphere collides with another sphere of identical mass. After collision, the two spheres move. The collision is inelastic. Then the angle between the directions of the two spheres is
Different from
![](https://search-static.byjusweb.com/question-images/byjus/ckeditor_assets/pictures/891740/original_10.png)
- 0 m/s
- 22.4 m/s
- 11.2 m/s
- 10 m/s