Time of Flight
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[g is the acceleration due to gravity]
- t=23√(hg)
- t=1.8√hg
- t=3.4√(hg)
- t=√2h3g
- u2√1+cos2θ
- u2√1+2cos2θ
- u2√1+3cos2θ
- u2√1+4cos2θ
If for a given angle of projection, the horizontal range is doubled, the time of flight becomes
- √4g
- √3g
- √5g
- √g
- 5 sec
- 0.625 sec
- 2.5 sec
- 1.25 sec
- 2Rg
- Rg
- R2g
- R4g
A body is thrown with a velocity of 9.8 m/s making an angle of 30∘ with the horizontal. It will hit the ground after a time
1.5 s
1 s
3 s
2 s
- 98.0 m/s
- 24.5 m/s
- 49.0 m/s
- 73.5 m/s
- 2√gh
- √gh
- √3gh
- √2gh
- 0.20 s
- 0.30 s
- 0.45 s
- 4.5 s
Neglecting the air resistance, the time of flight of a projectile is determined by
Uhorizontal
U=U2vertical+U2horizontal
U=U(U2vertical+U2horizontal)12
Uvertical
- 20√2 m
- 10 m
- 10√2 m
- 20 m
The friction of the air causes vertical retardation equal to one tenth of the acceleration due to gravity (Take g = 10ms−2). The time of flight will be decreased by
- HA=HB
- HA<HB
- TA=TB
- TA<TB
- The stone passes over the wall during ascent.
- The stone passes over the wall during descent.
- The difference in velocity at the initial and final point on ground is zero.
- The difference in speed at the initial and final point on ground is zero.
- Both must have same time of flight
- Both must achieve same maximum height
- A must have more horizontal range than B
- Both may have same time of flight
A particle is thrown with velocity u at an angle α from the horizontal. Another particle is thrown with the same velocity at an angle α from the vertical. The ratio of times of flight of two particles will be
- A and B, both feel that the body is coming (going) down.
- A and B, both feel that the body is going up.
- A feels that the body is coming down, while B feels that the body is going up.
- A feels that the body is going up, while B feels that the body is stationary.
A ball thrown by a boy is caught by another after 2 sec. some distance away in the same level. If the angle of projection is 30∘, the velocity of projection is
None of these
19.6 m/s
9.8 m/s
14.7 m/s
- √Gm2d
- √Gmd
- √2Gm3d
- √Gm3d
(M is mass and R is Radius of earth)
- R2
- R
- 54R
- 3R2
The maximum height reached by the projectile is . The horizontal range is . The velocity of projection in Is (g - acceleration due to gravity)
- 10√3 s
- 10 s
- 10√2 s
- 20√2 s
- Both particles will reach at ground simultaneously
- Both particles will reach at ground with same speed
- Particle (A) will reach at ground first with respect to particle (B)
- Particle (B) will reach at ground first with respect to particle (A)
At what angle should a projectile with initial velocity v be thrown, so that it achieves its maximum range?
- 3.0 s
- 2.0 s
- 1 s
- 1.5 s
- 25 m/s
- 25√2 m/s
- 25√3 m/s
- 252 m/s
- tan−1(34)
- tan−1(43)
- Not obtainable from the given data
- sin−1(34)