PV Work
Trending Questions
Q.
Why is the work done is a path function?
Q. A gas expands from 6m3 to 8m3 in a container against a constant external pressure of 3 Pa. The work done by the gas is:
- - 2 J
- 6 J
- + 18 J
- None of these
Q. An ideal gas is compressed to half its initial volume by means of several process. Which of the process results in maximum work done on the gas?
- Adiabatic
- isobaric
- isothermal
- Equal in all of above.
Q. An ideal gas is compressed to half its initial volume by means of several process. Which of the process results in maximum work done on the gas?
- Adiabatic
- isobaric
- isothermal
- Equal in all of above.
Q.
1 g H2 gas as STP is expanded so that volume is doubled. Hence, work done is
22.4 L atm
5.6 L atm
111.2 L atm
1.135 kJ
Q.
An ideal gas expands in volume from 1 × 10−3 to 1 × 10−2 m3 at 300 K against a constant pressure of 1 × 105 Nm−2. The work done is
270 kJ
−270 kJ
−900 J
900 kJ
Q. The area under a PV graph gives the work done.
- True
- False
Q. One mole of an ideal gas is taken from a to b along two paths denoted by the solid and the dashed lines as shown in the graph below. If the work done along the solid line path is Ws and that along the dotted line path is Wd, then the integter closest to the ratio Wd/Ws is
(2010)
(2010)
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