Van't Hoff Factor
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- 153.9 g of sucrose is dissolved in 500 mL of solution
- 0.3 M aq. Na2SO4 solution undergoing 100% ionization
- 1.8% w/w aq.NaOH solution undergoing 100% ionization
- 1.2 M benzoic acid in a solution of benzene where the acid dimerizes to an extent of 50%
- 1+α
- 1−α
- 1+2α
- 1−α
- α=i−1(x+y−1)
- α=i−1(x+y+1)
- α=x+y−1i−1
- α=(x+y+1)i−1
Here,
n is the number of molecules associate to form n-mer
β is the degree of dissociation
- i=2+[1n−1]β
- i=1+[n−1]β
- i=1+[1n−1]β
- i=1+[1n+1]β
- 0.5
- 0.4
- 0.7
- 0.9
The Van't Hoff factor calculated from association data is always ________ than calculated from dissociation data.
Less
More
Same
More or less
- 0.77%
- 1.6%
- 0.0060%
- 0.013%
Van't Hoff factor i can be best described as:
Less than one in case of dissociation
More than one in case of association
(Assume 100% ionisation)
The vapour pressure of pure water at 1000c is 760mm of Hg while that of dilute solution of urea is 740mm of Hg. Then mass of urea present in 7.60g water is
- 0.67g
6.7g
7.6g
0.76g
- 1.6
- 2.6
- 3.6
- 4.6
Column IColumn IIa. K4[Fe(CN)6]p. 1b. Fe2(SO4)3q. 1+4αc. C6H12O6r. 1+αd. BaCl2s. Greater than 1t. Less than 1
- (a - q ; b - s; c - p; d - s)
- (a - q, s;b - q, s;c - p; d - s)
- (a - q, s;b - q, s;c - p, s; d - s)
- (a - q, s;b - q, s;c - p, s; d - p, s)
- 100%
- 75%
- 50%
- 12.5%
Which of the following compounds corresponds Van't Hoff factor to be equal to 2 for dilute solution:
Sugar
xm=aP1+bP
The value of a and b are, respectively:
where,
ka and kd are rate constant of adsorption and desorption respectively.
K1 is proportionality constant.
- kakd and kakd
- K1kakd and kakd
- K1kakd and kdka
- K1kdka and kakd
25.4g of I2 and 14.2g of Cl2 are made to react completely to yield a mixture of ICl and ICl3 .Calculate moles of ICl and ICl3 formed.
0.1, 0.1
0.2, 0.2
0.1, 0.2
0.2, 0.1
- 1+α
- 1−α
- 1+2α
- 1−α
- 0.5
- 1
- 2
- 3
- Mass of AgCl precipitated is 861 g
- The clear solution will show an osmotic pressure of 98.52 atm
- The clear solution will show an osmotic pressure of 65.68 atm
- 2 moles of [Cr(H2O)6](NO3)3 will be present in the solution
- 49%
- 59%
- 79%
- 69%
- 1+α
- α
- 1+2α
- 1−2α
(JEE MAIN 2021)
Which one of the following electyrolytes has the same value of van’t Hoff factor (i) as that of Al2(SO4)3 (if all are 100% ionized)?
Al(NO3)3
K4[Fe(CN)6]
K2SO4
K3[Fe(CN)6]
A 5.25% solution of a substance is isotonic with a 1.5% solution of urea (molecular mass = 60g/mole) in the same solvent . If the densities of both the solutions are assumed to be equal to 1g/cc, molar mass of substance will be
- 210.0g/mole
- 90.0g/mole
- 115.0g/mole
- 105.0g/mole
The ratio of the value of any colligative property for KCl solution to that for sugar solution is nearly:
1
0.5
2.0
3
Considering complete ionization, Van't Hoff factor of Ca(NO3)2 is:
1
2
3
4
- ±1
- 1
- <0
- >1
One mole of a solute A is dissolved in a given volume of a solvent. If solute undergoes association, it's Van't Hoff factor i is expressed as: