Examples
Trending Questions
Q. ∫{1+2 tan x(tan x+sec x)}12 dx is equal to
- ln |sec x(sec x−tan x)|+c
- ln |cosec x(sec x+tan x)|+c
- ln |sec x(sec x+tan x)|+c
- ln |(sec x+tan x)|+c
Q. The momentum p of a particle changes with time according to the relation: dpdt=(10+2t) N. If the momentum is zero at t=0 s. What will the momentum in Ns at t=10 s
Q. If v=(4t2+5t+1) m/s is the expression according to which the velocity of a particle varies, then the expression for instantaneous displacement at any time t will be (Assume s=0 at t=0)
- 43t3+52t2+t
- 4t3+t+1
- 43t3+52t2+t+1
- 3t3+5t2+t
Q.
Consider the following two statements
1.Linear momentum of a system of particles is zero
2.Kinetic energy of a system of particles is zero
Then
1 implies 2 and 2 implies 1
1 does not imply 2 and 2 does not imply 1
1 implies 2 but 2 does not imply 1
1 does not imply 2 but 2 implies 1
Q.
The charge flown through a circuit in the time interval between t and t+dt is given by dq=e−t/τdt, where τ is a constant. Find the toatal charge flown through the circuit t = 0 to t = τ
τ(1e−1)
τ(1−1e)
τ(1+1e)
None of these
Q. ∫sin2xcosxdx=?
- 12cos2x+c
- 13cos3x+c
- 12sin2x+c
- 13sin3x+c
Q. ∫sin2xcosxdx=?
- 12cos2x+c
- 12sin2x+c
- 13cos3x+c
- 13sin3x+c
Q. Find the integral of ∫1(x+2)(x+3)dx
- loge(x+2)(x+3)+C
- loge(x+2)+loge(x+3)+C
- loge(x+3)(x+2)+C
- None of these
Q. ∫{1+2 tan x(tan x+sec x)}12 dx is equal to
- ln |sec x(sec x−tan x)|+c
- ln |cosec x(sec x+tan x)|+c
- ln |sec x(sec x+tan x)|+c
- ln |(sec x+tan x)|+c