Thermal Expansion
Trending Questions
If the earth were to suddenly contract to 1/nth of its present radius without any change in its mass, the duration of the new day will be nearly
24/n hr
24nhr
24/n2hr
24n2hr
Find the expression for the time period of a pendulum using dimensional analysis.
k√gl
kl
k√lg
klg
When two ends of a rod wrapped with cotton are maintained at different temperatures and after some time every point of the rod attains a constant temperature, then
Conduction of heat at different points of the rod stops because the temperature is not increasing
Rod is bad conductor of heat
Heat is being radiated from each point of the rod
Each point of the rod is giving heat to its neighbour at the same rate at which it is receiving heat
Solids expand on heating because
Kinetic energy of the atoms increases
Potential energy of the atoms increases
Total energy of the atoms increases
The potential energy curve is asymmetric about the equilibrium distance between neighbouring atoms
[ α=1.70×10−5/ ∘C ].
- 1.44×10−2 cm
- 1.96×10−2 cm
- 1.78×10−2 cm
- 1.28×10−2 cm
- 75242kL2α2(ΔT)2
- 27242kL2α2(ΔT)2
- 81242kL2α2(ΔT)2
- 49242kL2α2(ΔT)2
- 60.015
- 60.024
- 60.400
- 60.600
The Unit of Coefficient of Linear Expansion is _______
- bends with steel on concave side
- bends with copper on concave side
- dose not expand
- data is insufficient
[ given, α1α2=2 ]
- R5
- 2R
- 5R
- R2
- 2:3
- 1:1
- 3:2
- 4:9
[Znα=30×10−6/ ∘ C, Cuα=17×10−6/ ∘ C]
- Zinc strip will be on outer side of arc.
- Copper strip will be on outer side of arc.
- Bimetal will not bend.
- Data insufficient
Identify the device shown in figure.
A cylindrical metal rod of length L0 is shaped into a ring with a small gap as shown. On heating the system -
x decreases, r and d increase
x and r increase, d decreases
x, r and d all increase
- Data insufficient to arrive at a conclusion
A litre of alcohol weighs
Less in winter than in summer
Less in summer than in winter
Some both in summer and winter
None of the above
- πD2αΔT(αΔT+2)
- πD2αΔT(αΔT−2)
- πD2αΔT(αΔT+4)
- πD2αΔT(αΔT−4)
- 2αΔt
- αΔt
- 3αΔt
- 4αΔt
- 5.18 s gain
- 5.18 s lose
- 36.28 s gain
- 36.28 s lose
- 5.18 s gain
- 5.18 s lose
- 36.28 s gain
- 36.28 s lose
- 10.4 seconds faster
- 10.4 minutes faster
- 1 minute slower
- 10.4 seconds slower
[ α1=2×10−5 ∘C−1, α2=5×10−5 ∘C−1,
Y1=2×1010 N/m2, Y2=1010 N/m2 ]
- 15×10−5 m
- 12×10−5 m
- 10×10−5 m
- 18×10−5 m
When a bimetallic strip is heated, it
Does not bend at all
Gets twisted in the form of an helix
Bend in the form of an arc with the more expandable metal outside
Bends in the form of an arc with the more expandable metal inside
- πD2αΔT(αΔT+2)
- πD2αΔT(αΔT−2)
- πD2αΔT(αΔT+4)
- πD2αΔT(αΔT−4)
[ α=1.70×10−5/ ∘C ].
- 1.44×10−2 cm
- 1.96×10−2 cm
- 1.78×10−2 cm
- 1.28×10−2 cm
Given, αCu=1.7×10−5∘C−1
- 90 cm
- 90.01 cm
- 90.3 cm
- 90.03 cm
- 186400per∘C
- 143200per∘C
- 114400per∘C
- 128800per∘C
α1 and α2. If we take a brass rod of length l1 and steel rod of length l2 at 0∘C, their difference in length (l2−l1)will remain the same at a temperature if
- α1l2=α2l1
- α1l22=α2l21
- α21l1=α22l2
- α1l1=α2l2
A pendulum clock keeps correct time at 0∘. Its mean coefficient of linear expansions is α/∘, then the loss in seconds per day by the clock if the temperature rises by t∘ is
12αt×8640001−αt2
12αt×86400
12αt×86400(1−αt2)2
12αt×8464001+αt2
- 71.25 cm and 41.25 cm
- 82 cm and 52 cm
- 92 cm and 62 cm
- 62.25 cm and 32.25 cm
- 80.08 cm
- 79.92 cm
- 81.12 cm
- 79.62 cm