Wave Equation
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The displacement of the particle at of a stretched string carrying a wave in the positive x-direction is given by . The wave speed is . Write the wave equation.
The equation of a wave traveling on a string stretched along the X-axis is given by.
(a) Write the dimensions of
(b) Find the wave speed.
(c) In which direction is the wave traveling?
(d) Where is the maximum of the pulse located at
- Wave number is π15 cm−1
- Time period of wave is 16 s
- Value of phase constant is π2
- Speed of wave is 1.8 m/s
- y=2cos(3x)sin(10t)
- y=2√x−5t
- y=2sin(5x−2t)+2cos(5x−2t)
- y=5sin(100πt−5x)
- x = A sin (ky - ωt)
y = A sin (kx - ωt)
- y = A sin kycosωt
- x = A sin (ky - λt)
- y=0.05 sin 2π(4000t−12.5x)
- y=0.05 sin 2π(4000t−122.5x)
- y=0.05 sin 2π(3300t−10x)
- y=0.05 sin 2π(3300x−10t)
- y(x.t)=0.02sin[(2πx)+(10πt)] m
- y(x.t)=0.02cos[(10πx)+(2πt)] m
- y(x.t)=0.02sin[(2πx)−(10πt)] m
- y(x.t)=0.02sin[(πx)+(5πt)] m
- 1.5 m/s
- 2 m/s
- 1 m/s
- 0.5 m/s
y=2√3sinπ(x−2t+16)
- Both of the above graphs are possible
- None of the two graphs are possible
- 3 m/s
- –3 m/s
- 8 m/s
- –8 m/s
- 5 m/s
- 6 m/s
- 6 mm/s
- 3 mm/s
- 2.1 cm
- 4 cm
- 3 cm
- 7.86 cm
A simple harmonic wave is represented by the relation y(x, t)=a0 sin 2π(vt−xλ) If the maximum particle velocity is three times the wave velocity, the wavelength λ of the wave is
πa03
2πa03
πa0
πa02
- It represents a wave propagating along positive x− axis with a velocity of 30 m/s
- It represents a wave propagating along negative x− axis with a velocity of 120 m/s
- It represents a wave propagating along negative x− axis with a velocity of 30 m/s
- It represents a wave propagating along negative x− axis with a velocity of 104 m/s
- y(x, t)=(0.02m) sin [(2πm−1)x+(10πs−1)t]m
- y(x, t)=(0.02m) cos (10πs−1)t+(2πm−1)×m
- y(x, t)=(0.02m) sin [(2πm−1)x−(10πs−1)t]m
- y(x, t)=(0.02m) sin [(πm−1)x+(5πs−1)t]m
- 0.48 m
- 0.96 m
- 0.24 m
- 0.12 m
- λ0=πA3
- λ0=2πA3
- λ0=πA
- λ0=3πA
y=0.025sin(100t+0.25x)
Which of the following represents the velocity of the particle of medium through which the sinusoidal wave is propagating?
- 2.5cos(100t+0.25x)
- 50cos(100t+0.25x)
- 5sin(100t+0.25x)
- 20sin(50t+0.25x)
- y=sin(x−2t)
- y=sin(2πx−2πt)
- y=sin(10πx−20πt)
- y=sin(2πx+2πt)
y=2√3sinπ(x−2t+16)
- Both of the above graphs are possible
- None of the two graphs are possible
- y=2(t−x2)2+1
- y=2(t−x4)2+1
- y=2(t−2x)2+1
- y=2(t−4x)2+1
- 10 m/s
- 15 m/s
- 25 m/s
- 20 m/s
A plane sound wave is travelling in a medium. In reference to a frame A, its equation is y=a cos (ωt−kx). Which reference to frame B, moving with a constant velocity v in the direction of propagation of the wave, equation of the wave will be
y=acos[(ω+kv)t–kx]
- y=−acos[(ω−kv)t−kx]
- y=acos[(ω−kv)t−kx]
- y=acos[(ωt+kv)t+kx]
- y=Asin(kx−ωt)
- y=Asin2(kx−ωt)
- y=Asin(k2x2−ω2t2)
- y=Asin(kx+ωt+π10)
- y(x, t)=0.12sinπ[x−2000 t] m
- y(x, t)=0.12sin[31.4 x−6200 t] m
- y(x, t)=0.12sin[3.14 x−6283 t] m
- y(x, t)=0.12sin[31.4 x−6283 t] m
- y=(0.06m) cos[78.5 m−1)x+(2356.2 s−1)t]m
- y=(0.06m) sin [(78.5m−1)x−(2356.2s−1)t]m
- y=(0.06m) sin [(78.5m−1)x+(2356.2s−1)t]m
- y=(0.06m) cos[(78.5m−1)x−(2856.2s−1)t]m
What is the equation of a sinusoidal wave moving in the positive x direction with wave length 6 m and time period 0.5s. The amplitude of the wave is 5 m.
y=6sin(2π5x−4πt)
y=5sin(π3x−4πt)
y=5sin(x−t)
None of these
- y=0.05 sin 2π(4000t−12.5x)
- y=0.05 sin 2π(4000t−122.5x)
- y=0.05 sin 2π(3300t−10x)
- y=0.05 sin 2π(3300x−10t)
- zero
- half of the amplitude
- equal to the amplitude
- none of these