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Question

A(-3, -4) , B(3, 0) , C(-5, 0) are the vertices of ABC. Find the co-ordinates of the circumcentre of ABC.

A
(12,12)
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B
(12,2)
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C
(2,12)
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D
(1,12)
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Solution

The correct option is D (1,12)

Let P(x,y) be the circumcentre of ABC.
Point P is equidistant from A,B & C.
PA=PB=PC
PA2=PB2=PC2(i) [on squaring]

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