(a+b+c+d+e)(v+w+x+y+z)=N, where a, b, c, d, e are five consecutive even integers and v, w, x, y, z are five consecutive odd integers. If v=a+1 and n represents natural numbers, then which of the following is the most suitable value of N?
A
(n+4)(n+5)
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B
(n+3)(n+4)
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C
(n+2)/(n+3)
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D
100(n+2)(n+2.5)
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Solution
The correct option is D100(n+2)(n+2.5) Giventhatv=a+1∵visodd⇒aiseven.Sowecanreplaceaby2nwhennisnaturalnumber.∴v=2n+1.∴Thegivenproductis(a+b+c+d+e)(v+w+x+y+z)=NAsperthegivenconditionwecanwriteN=(a+a+2+a+4+a+6+a+8)×(a+1+a+3+a+5+a+7+a+9)=(5a+20)(5a+25)Replacingaby2nN=(5×2n+20)(5×2n+25)=100(n+2)(n+2.5)∴AnswerDiscorrect.