A-B-H2O - NH4HCO3NH4HCO3-NaCl - C- NH4ClNH4Cl-D - 2NH3-2H2O-CaCl2Sum of the atoms present in one molecule of each of A- B- C and D

The equations for complete solvay process can be written as: A2NH_3+H_2O+BCO_2→ (NH_4)_2CO_3 (NH_4)_2CO_3+H_2O+CO_2→ 2NH_4HCO_3 NH_4HCO_3+NaCl → NH_4Cl+CNaHCO_ ...

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Byju's Answer

Standard XII

Chemistry

Sodium Thiosulphate

A+B+H2O → NH4...

Question

$A + B + H_{2} O \to (N H_{4}) H C O_{3} N H_{4} H C O_{3} + N a C l \to C + N H_{4} C l N H_{4} C l + D \to 2 N H_{3} + 2 H_{2} O + C a C l_{2}$
Sum of the atoms present in one molecule of each of $A, B, C and D$

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Solution

The equations for complete solvay process can be written as:
$2 N H_{3} A + H_{2} O + C O_{2} B \to (N H_{4})_{2} C O_{3} (N H_{4})_{2} C O_{3} + H_{2} O + C O_{2} \to 2 N H_{4} H C O_{3} N H_{4} H C O_{3} + N a C l \to N H_{4} C l + N a H C O_{3} C$
In this process, $N H_{3}$ is recovered when the solution containing $N H_{4} C l$ is treated with $C a (O H)_{2}$ .
$2 N H_{4} C l + C a (O H)_{2} D \to 2 N H_{3} + C a C l_{2} + 2 H_{2} O$
Here,
$A = N H_{3} B = C O_{2} C = N a H C O_{3} D = C a (O H)_{2}$
Sum of the atoms present in one molecule of each of $A, B, C and D = 18$

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Similar questions

Q. Find

A, B

and

C

in the following reactions:

$N H_{3} + A + C O_{2} \to {(N H_{4})}_{2} C O_{3}$

${(N H_{4})}_{2} C O_{3} + H_{2} O + B \to N H_{4} H C O_{3}$

$N H_{4} H C O_{3} + N a C l \to N H_{4} C l + C$