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Question

A ball of mass 0.2Kg is thrown vertically upwards by applying a force by hand. If the hand moves 0.2m while applying the force and the ball goes up to 2m height further, find the magnitude of the force. (take, g=10ms2)


A

4N

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B

16N

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C

20N

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D

22N

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Solution

The correct option is D

22N


Step 1: Given data

Given, mass of a ball, m=0.2Kg

Total height of a ball, h=h1+h2

Here,

h1=heightofaballwhenitisinhand=0.2mh2=heightofaballafterreleasingitfromhand=2m

Total height attained by a ball,h=0.2+2=2.2m

Let force applied=F

Distance for which force is applied, S=0.2m

Step 2: Calculating the magnitude of force

Now we know that work done by a force is equal to potential energy. Hence,

F.S=mghF=mghSF=0.2×10×2.20.2F=22N

So the force applied on a ball is equal to 22N.

Hence, option(D) is correct answer.


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