Question

A basketball court layout is designed as shown below. Find the area of the court except the area within the three-point line.
($Assume\pi =3.14$)

• A. 405.66 yd
• B. 660 yd
• C. 254.34 yd
• D. 354.66 yd

Answer 1

The correct option is A 405.66 yd

A basketball court is rectangular in shape.


Given:
Length of the court = 30 yd
Width of the court = 22 yd

The three-point line area is the area marked in yellow.

We can see that the yellow-colored portion is in the form of a semicircle.

Since 1 yd on either side is removed, the diameter of the semicircle $=20–2=18$

$\text{Radius of the semicircle}=\frac{18}{2}=9$

We can see that the two semicircles on either side of the court would make a complete circle of radius 9 yd.

Area other than the three-point line = Area of rectangle – Area of circle of radius 9 yd

$=30\times 22–\pi 9^2$

$=660–3.14\times 81$

$=660–254.34$

$=405.66\text{yd}$