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Finding Average Velocity

A bird moves ...

Question

A bird moves from point $(1 m, - 2 m, 3 m)$ to $(4 m, 2 m, 3 m)$ . If the speed of the bird is $10 m / s$ , then the velocity vector of the bird in $m / s$ is:-

5 (\begin{matrix} ^i - 2^j + 3^k \end{matrix})

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5 (\begin{matrix} 4^i + 2^j + 3^k \end{matrix})

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0.6^i + 0.8^j

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6^i + 8^j

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Solution

The correct option is D $6^i + 8^j$
$^v = \frac{(\begin{matrix} 4 - 1 \end{matrix})^i + (\begin{matrix} 2 + 2 \end{matrix})^j + (\begin{matrix} 3 - 3 \end{matrix})^k}{\sqrt{{(\begin{matrix} 4 - 1 \end{matrix})}^{2} + {(\begin{matrix} 2 + 2 \end{matrix})}^{2} + {(\begin{matrix} 3 - 3 \end{matrix})}^{2}} = \frac{3}{5}^i + \frac{4}{5}^j}$

$\to v = (\begin{matrix} 10 \end{matrix}) (\begin{matrix} \frac{3}{5}^i + \frac{4}{5}^j \end{matrix}) = 6^i + 8^j$

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Similar questions

A

(1, - 2, 3)

B

(4, 2, 3)

10 m/s

A

(1, - 2, 3)

B

(4, 2, 3)

10 m/s

m_{a} = 3 kg

10 m/s

m_{b} = 2 kg

\to P =^i - 2^j + 3^k, \to Q = -^i + 3^j -^k

\to R = 2^i - 4^j + 3^k

A

4^i - 3^j - 2^k

B

6^i +^j - 3^k

A f o r c e \to F = 4^i - 5^j + 3^k i s a c t i n g a p o i n t - - \to r_1 =^i + 2^j + 3^k

- - \to r_1 = 3^i - 2^j - 3^k

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