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Question

A bomb is dropped on an enemy post by an aeroplane flying horizontally with a velocity of 60 km/h1 and at a height of 490 m. At the time of dropping the bomb, how far should the aeroplane be from the enemy post so that the bomb may directly hit the target?

A
4003 m
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B
5003 m
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C
17003 m
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D
498 m.
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Solution

The correct option is B 5003 m
Height of the aeroplane from the ground =490 m

Using second equation of motion,
h=uyt+12gt2
uy=0
t=2hg=2×4909.8 s=100 s=10 s

Let x be the distance between the target and the aeroplane when the bomb is dropping from the aeroplane.
x=vt=(60×518) ms1×10 s=5003 m

Alternate Solution:
Horizontal distance covered by a body falling from height h with initial horizontal velocity u.
x=u2hg=60×518×2×4909.8=60×518×10=5003 m

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