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Question

A box contains 50 discs which are numbered from 1 to 50. If one disc is drawn at random from the box, find the probability that is bears
(i) A two digit number less than 30
(ii) A prime number
(iii) A number divisible by 3

A
(i) 15 (ii) 712 (iii) 735
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B
(i) 25 (ii) 310 (iii) 825
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C
(i) 15 (ii) 1318 (iii) 1118
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D
None of these
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Solution

The correct option is B (i) 25 (ii) 310 (iii) 825
Total number of discs are 50 which are numbered from 1 to 50.
(1) Two digit number less than 30 are:- 10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29
Here favorable discs =20
∴ probability = 2050=25
(ii) prime numbers between 1 to 50 are:-
2,3,5,7,11,13,17,19,23,29,31,37,41,43,47
Here favorable discs =15
∴ probability = 1550=310
(iii) Numbers divisible by 3 between 1 to 50 are:-
3,6,9..............48
So, total number of favorable discs =16.
∴ probability = 1650=825

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