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Standard XII

Physics

1st Law of Thermodynamics

A boy eats an...

Question

A boy eats an ice cube of mass $100$ gm at $0^{o} C$ . If the body temperature of the boy is $37^{o} C$ the number of joules of energy lost by the boy is :
( $L_{i c e} =$ 330 KJ/kg ;Specific heat of water = $4200 J k g^{- 1} K^{- 1}$ )

48540 J

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39140 J

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49000 J

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29140 J

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Solution

The correct option is A $48540 J$
Energy lost by the boy is equal to the heat energy gained by the ice cube.
Let's assume that the final temperature of water after melting is 37 $^{o}$ C
Heat energy $= m L_{i c e} + m C Δ T = 100 (330 + 4.2 (37 - 0)) = 48540 J$

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Similar questions

Q. The amount of heat energy required to convert

1

kg of ice at

- 10^{\circ} C

to water at

100^{\circ} C

7, 77, 000

J. Calculate the specific latent heat of ice. Specific heat capacity of ice

2100 J k g^{- 1} K^{- 1}

, specific heat capacity of water =

4200 J k g^{- 1} K^{- 1}

Q. A piece of ice of mass

40 g

0^{o} C

is added to

200 g

of water at

50^{\circ} C

. Calculate the final temperature of water when all the ice has melted. Specific heat capacity of water =

4200 J k g^{- 1} K^{- 1}

and specific latent heat of fusion of ice =

336 \times 10^{3} J k g^{- 1}

Q. If the temperature of 10 kg of water is raised by

10^{o} C

, then the heat energy supplied to water is _________ . (specific heat capacity of water is

4200 J k g^{- 1} K^{- 1}

)

40 g

of ice at

0^{o} C

is used to bring down the temperature of certain mass of water at

60^{o} C t o 10^{o} C

. Find the mass of water used.
[Specific heat capacity of water

= 4200 J K g^{- 1} C^{- 1}

[Specific latent heat of fusion of ice

= 336 \times 10^{3} J k g^{- 1}

]

Q. An ice cube of mass

0.1 K g

0^{o} C

is placed in an isolated container which is at

227^{o} C

. The specific heat

s

of the container varies with temperature

T

according to the empirical relation

s = A + B T,

where

A = 100 c a l k g^{- 1} K^{- 1}

and

B = 2 \times 10^{- 2} c a l k g^{- 1}

.
If the final temperature of the container is

27^{o} C

, the mass of the container is (Latent heat of fusion of water

= 8 \times 10^{4} c a l k g - 1,

Specific heat of water=

10^{3} c a l k g^{- 1} K^{- 1}

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A boy eats an ice cube of mass 100 gm at 0oC. If the body temperature of the boy is 37oC the number of joules of energy lost by the boy is :(Lice=330 KJ/kg ;Specific heat of water =4200J kg−1K−1)

The correct option is A 48540JEnergy lost by the boy is equal to the heat energy gained by the ice cube.Let's assume that the final temperature of water after melting is 37oCHeat energy =mLice+mCΔT=100(330+4.2(37−0))=48540J

A boy eats an ice cube of mass $100$ gm at $0^{o} C$ . If the body temperature of the boy is $37^{o} C$ the number of joules of energy lost by the boy is :
( $L_{i c e} =$ 330 KJ/kg ;Specific heat of water = $4200 J k g^{- 1} K^{- 1}$ )

The correct option is A $48540 J$
Energy lost by the boy is equal to the heat energy gained by the ice cube.
Let's assume that the final temperature of water after melting is 37 $^{o}$ C
Heat energy $= m L_{i c e} + m C Δ T = 100 (330 + 4.2 (37 - 0)) = 48540 J$