A boy walks a distance $30 m$ in $1$ minute and another $30 m$ in $1.5$ minute. Describe the type of motion of the boy and find his average speed in $m s^{- 1}$ .

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Solution

The boy walks a distance $30 m$ in $1$ minute and another $30 m$ in $1.5$ minute, it means the boy covers unequal distances in equal time intervals. Thus, the motion is non-uniform.
Given, Total distance travelled $= (30 + 30) m$
$= 60 m$
Time taken taken $= (1 + 1.5) m i n$
$= 2.5 m i n = 150 s e c$
To find, Average speed:

$Average speed = \frac{Total distance covered}{Time taken}$

$= \frac{60 m}{150 s e c} = 0.4 m s^{- 1}$
So, the average speed of car is $0.4 m s^{- 1}$ .

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Time and Work

Standard VII Mathematics

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A boy walks a distance 30m in 1 minute and another 30m in 1.5 minute. Describe the type of motion of the boy and find his average speed in ms−1.​

A boy walks a distance $30 m$ in $1$ minute and another $30 m$ in $1.5$ minute. Describe the type of motion of the boy and find his average speed in $m s^{- 1}$ .